Rearranging Formulas
Key Ideas
Key Terms
- subject
- Of a formula is the variable that stands alone on one side.
- inverse operations
- In reverse order (undo the last operation first).
Making a New Variable the Subject
The process is identical to solving an equation — isolate the target variable using inverse operations.
Worked Example
Question: Make t the subject of v = u + at.
Step 1 — Subtract u from both sides.
v − u = at
Step 2 — Divide both sides by a.
(v − u)⁄a = t
Step 3 — Write with the subject on the left.
t = (v − u)⁄a
What Does "Changing the Subject" Mean?
Rearranging a formula (also called changing the subject) means rewriting it so that a different variable is isolated on one side. For example, the formula v = u + at has v as the subject. We might need to rearrange it to make a the subject (to find acceleration) or u the subject (to find initial speed).
The process is exactly the same as solving an equation — use inverse operations to move everything except the target variable to the other side. The difference is that letters remain on both sides throughout.
Single-Step Rearrangements
Start with simple formulas that need only one inverse operation.
Example 1: Make m the subject of E = mc2. Divide both sides by c2: m = E/c2.
Example 2: Make C the subject of F = (9/5)C + 32. Subtract 32: F − 32 = (9/5)C. Multiply by 5/9: C = (5/9)(F − 32). This is the Celsius to Fahrenheit conversion rearranged.
Multi-Step Rearrangements
More complex formulas require several steps. A useful strategy: work out what sequence of operations was applied to the target variable in the original formula, then undo them in reverse order.
Example: Make a the subject of v = u + at.
Step 1 — subtract u from both sides: v − u = at.
Step 2 — divide both sides by t: a = (v − u)/t.
Example: Make r the subject of A = πr2.
Step 1 — divide by π: A/π = r2.
Step 2 — take the square root of both sides: r = √(A/π). Note: we take the positive root since r is a length.
Formulas Involving Fractions and Roots
When the target variable is in a denominator, multiply both sides by the denominator first to clear the fraction. When the target variable is under a square root, isolate the root and then square both sides.
Example: Make r the subject of T = 2π√(l/g).
Step 1 — divide by 2π: T/(2π) = √(l/g).
Step 2 — square both sides: T2/(4π2) = l/g.
Step 3 — multiply by g: l = gT2/(4π2). (Here l is the subject, not r — this shows the process for a pendulum formula.)
Why Rearranging Matters
Rearranging formulas is a powerful practical skill. Scientists rearrange E = mc2 to find mass when energy is known. Engineers rearrange speed formulas to find time. In exams, you will often be given a formula and asked to "find x" where x is not the subject — rearranging first makes the calculation straightforward.
Mastery Practice
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Rearrange each formula to make the indicated variable the subject. Show every step. Fluency
- A = lw, make l the subject.
- P = 2(l + w), make l the subject.
- v = u + at, make u the subject.
- v = u + at, make a the subject.
- d = st, make s the subject.
- d = st, make t the subject.
- I = Prt ÷ 100, make r the subject.
- I = Prt ÷ 100, make t the subject.
- F = ma, make m the subject.
- C = 2πr, make r the subject.
- y = mx + c, make x the subject.
- y = mx + c, make m the subject.
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Rearrange each formula to make the indicated variable the subject. These involve squares or square roots. Fluency
- A = πr², make r the subject.
- E = ½mv², make v the subject.
- c² = a² + b², make a the subject.
- V = ¾πr³, make r the subject. (Leave in terms of π.)
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Rearrange the formula to make the indicated variable the subject, then substitute the given values to find its value. Understanding
- v = u + at. Make a the subject, then find a when v = 50, u = 10 and t = 8.
- P = 2(l + w). Make w the subject, then find w when P = 36 and l = 11.
- I = Prt ÷ 100. Make P the subject, then find P when I = 180, r = 6 and t = 5.
- A = πr². Make r the subject, then find r (to 1 d.p.) when A = 50.27 cm² (use π = 3.14).
- E = ½mv². Make m the subject, then find m when E = 450 J and v = 15 m/s.
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Identify whether the rearrangements shown are correct or incorrect. For any that are incorrect, show the correct working. Understanding
- From d = st, a student claims t = d − s. Is this correct?
- From A = ½bh, a student claims b = 2A ÷ h. Is this correct?
- From y = 3x − 7, a student claims x = (y + 7) ÷ 3. Is this correct?
- From c² = a² + b², a student claims a = c − b. Is this correct?
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Real-world formula applications. Rearrange then evaluate in context. Problem Solving
- The formula for average speed is v = d ÷ t.
- Rearrange to make d the subject.
- A cyclist maintains an average speed of 22 km/h for 2 hours and 15 minutes. How far do they travel?
- The formula for simple interest is I = Prt ÷ 100.
- Rearrange to make P the subject.
- An investor wants to earn $600 interest over 4 years at a rate of 5% per annum. How much must they invest?
- Celsius and Fahrenheit are related by F = 9C⁄5 + 32.
- Rearrange to make C the subject.
- Normal body temperature is 98.6°F. Convert this to Celsius.
- Water boils at 100°C. What is this in Fahrenheit?
- A rectangular field has a perimeter of 220 m and an area of 2800 m². Use P = 2(l + w) to find l and w. (Hint: find both unknowns by forming and solving a pair of equations.)
- The formula for average speed is v = d ÷ t.
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The kinematic formula s = ut + ½at² gives displacement s (m) with initial velocity u (m/s), acceleration a (m/s²) and time t (s). Problem Solving
- Rearrange to make u the subject.
- A car starts from rest (u = 0) and travels 80 m in 4 s. Find its acceleration using the rearranged formula.
- Using v = u + at, find the final velocity of the car from part (b).
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Rearrange each formula to make the indicated variable the subject. These involve fractions — multiply through before isolating. Problem Solving
- T = 2πr⁄v, make v the subject. (T = period, r = radius, v = speed.)
- R = V⁄I, make I the subject (Ohm’s Law).
- P = F⁄A, make A the subject (pressure formula).
- v² = u² + 2as, make s the subject.
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Two students rearrange the same formula differently. Determine which student (if either) is correct, or whether both forms are equivalent. Problem Solving
- Formula: E = mc². Make m the subject.
Student A writes: m = E ÷ c².
Student B writes: m = E ÷ (c × c).
Are both correct? Explain. - Formula: v² = u² + 2as. Make a the subject.
Student A writes: a = (v² − u²) ÷ (2s).
Student B writes: a = v² ÷ (2s) − u².
Which is correct? Show the correct working. - Formula: A = ½h(a + b) (area of trapezium). Make h the subject.
Student A writes: h = 2A ÷ (a + b).
Student B writes: h = 2A ÷ a + b.
Which is correct? Explain the error in the incorrect version.
- Formula: E = mc². Make m the subject.
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Each scenario requires you to choose and rearrange the correct formula. Show all working. Problem Solving
- A circle has an area of 113.1 cm². Use A = πr² to find its radius (to 1 d.p.).
- A cylindrical tank has volume V = πr²h. The tank is 2 m tall and holds 25.13 m³. Find its radius (to 1 d.p.).
- The formula for compound interest is A = P(1 + r)² for a two-year investment. Rearrange to make P the subject, then find P if A = $1210 and r = 0.1 (10%).
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Extended investigation — create and apply. Problem Solving
- Write down a formula of your own that contains at least three variables. Rearrange it twice to make two different variables the subject. Show all steps.
- The stopping distance of a car is given by d = v² ÷ (2μg), where v is speed, μ is the friction coefficient, and g = 10 m/s².
- Rearrange to make v the subject.
- A car stops in 40 m on a road where μ = 0.5. What was its speed in m/s?
- Convert this speed to km/h. (Multiply m/s by 3.6.)
- A rectangular swimming pool has length l = 2w + 3, where w is the width in metres. The perimeter formula is P = 2(l + w).
- Substitute the expression for l into the perimeter formula and simplify.
- If P = 54 m, find w and then l.
- Find the area of the pool.