Pythagorean and Reciprocal Identities
Key Terms
- Pythagorean identity
- sin²θ + cos²θ = 1 (fundamental; derived from the unit circle definition).
- Derived identities
- Divide by cos²θ: 1 + tan²θ = sec²θ. Divide by sin²θ: 1 + cot²θ = cosec²θ.
- Reciprocal identities
- sec θ = 1/cos θ; cosec θ = 1/sin θ; cot θ = cos θ/sin θ = 1/tan θ.
- Useful rearrangements
- sin²θ = 1 − cos²θ; tan²θ = sec²θ − 1; cot²θ = cosec²θ − 1.
- Proving identities
- Work on ONE side only (usually the more complex side); never cross the equals sign.
- Simplifying
- Look for Pythagorean substitutions: replace 1 − cos²θ with sin²θ, or 1 + tan²θ with sec²θ.
Pythagorean and Reciprocal Identities — Key Facts
Reciprocal identities:
sec θ = 1/cos θ cosec θ = 1/sin θ cot θ = cos θ/sin θ = 1/tan θ
Fundamental Pythagorean identity: sin²θ + cos²θ = 1
Derived Pythagorean identities:
Divide by cos²θ: tan²θ + 1 = sec²θ (i.e., 1 + tan²θ = sec²θ)
Divide by sin²θ: 1 + cot²θ = cosec²θ
Rearrangements to memorise:
sin²θ = 1 − cos²θ cos²θ = 1 − sin²θ tan²θ = sec²θ − 1 cot²θ = cosec²θ − 1
Worked Example 1 — Simplifying with Identities
Simplify: (a) (1 − cos²θ)/sinθ (b) sinθ · secθ
(a) Numerator: 1 − cos²θ = sin²θ (Pythagorean identity)
sin²θ/sinθ = sinθ
(b) sinθ · (1/cosθ) = sinθ/cosθ = tanθ
Worked Example 2 — Proving an Identity
Prove that (1 + tan²θ) cos²θ = 1.
Work on the LHS only:
LHS = sec²θ · cos²θ [since 1 + tan²θ = sec²θ]
= (1/cos²θ) · cos²θ = 1 = RHS ✓
Where Do the Identities Come From?
All trigonometric identities in this lesson flow from one source: the unit circle. A point on the unit circle has coordinates (cosθ, sinθ). Since it lies on the circle x² + y² = 1, we immediately get sin²θ + cos²θ = 1. This is not a formula to memorise in isolation — it is a direct statement of Pythagoras’s theorem applied to the unit circle, and everything else follows from it by algebraic manipulation.
The Reciprocal Functions
The reciprocal functions secant, cosecant, and cotangent are defined purely for convenience — they let us write expressions more compactly and avoid repeated fractions. It is crucial to know which function is the reciprocal of which:
secθ = 1/cosθ (secant is the reciprocal of cosine)
cosecθ = 1/sinθ (cosecant is the reciprocal of sine)
cotθ = cosθ/sinθ = 1/tanθ (cotangent is the reciprocal of tangent)
A common memory error is confusing sec and cosec. Remember: sec goes with cos (both contain the letter ‘c’ immediately after sec/cos).
Deriving the Other Pythagorean Identities
Starting from sin²θ + cos²θ = 1, we can divide through by cos²θ (wherever cosθ ≠ 0) to obtain:
sin²θ/cos²θ + 1 = 1/cos²θ
tan²θ + 1 = sec²θ
Similarly, dividing by sin²θ (wherever sinθ ≠ 0):
1 + cot²θ = cosec²θ
There are therefore three Pythagorean identities, all equivalent to each other. You should be able to move between them fluently.
Strategy for Simplifying Expressions
When simplifying or proving trig identities, build a mental toolkit of substitutions. Common strategies include:
1. Replace 1 − cos²θ with sin²θ (or vice versa).
2. Replace 1 + tan²θ with sec²θ.
3. Convert all functions to sin and cos — this is a reliable fallback strategy that always works, even if it is not always the most elegant.
4. Factorise — for example, sin4θ − cos4θ = (sin²θ + cos²θ)(sin²θ − cos²θ) = 1 × (sin²θ − cos²θ).
Proving Identities: The Golden Rule
The golden rule of proving identities is: work on each side independently. You cannot add, subtract, multiply, or divide both sides by the same thing (that would assume the identity is true before you prove it). Typically, start with the more complicated side and transform it, step by step, until it matches the simpler side. Each step must be a valid algebraic manipulation or a known identity substitution.
Common approaches: convert everything to sin and cos; look for Pythagorean identity patterns; factorise differences of squares; use algebra (multiply top and bottom by a conjugate expression).
Expressing One Ratio in Terms of Another
Given partial information about a trig ratio (for example, sinθ = 3/5 in the first quadrant), we can find all other ratios using the Pythagorean identities and CAST rule. For instance, sin²θ + cos²θ = 1 gives cosθ = ±√(1 − sin²θ), and the quadrant tells us the sign.
Mastery Practice
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Fluency
Q1 — Reciprocal Functions
Given sinθ = 5/13 and cosθ = 12/13, find: (a) cosecθ (b) secθ (c) tanθ (d) cotθ
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Fluency
Q2 — Evaluating Using Identities
Given tanθ = 3/4 and θ is in the first quadrant, find sinθ, cosθ, and secθ.
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Fluency
Q3 — Simplifying Trigonometric Expressions
Simplify: (a) sinθ · cotθ (b) cos²θ · sec²θ − 1 (c) (tanθ · cosecθ) / secθ
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Fluency
Q4 — Pythagorean Substitution
Simplify: (a) (1 − sin²θ)/cosθ (b) sec²θ − tan²θ (c) (cosec²θ − 1)/cosec²θ
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Understanding
Q5 — Proving an Identity (Basic)
Prove that tanθ + cotθ = secθ · cosecθ.
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Understanding
Q6 — Proving an Identity (Intermediate)
Prove that (sinθ + cosθ)² = 1 + 2 sinθ cosθ.
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Understanding
Q7 — Finding All Ratios Given One
Given that cosθ = −2/3 and θ is in the third quadrant (π < θ < 3π/2), find sinθ, tanθ, and cosecθ.
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Understanding
Q8 — Proving an Identity (Factorising)
Prove that (1 − cosθ)(1 + cosθ) = sin²θ.
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Problem Solving
Q9 — Complex Identity Proof
Prove that sin4θ − cos4θ = sin²θ − cos²θ.
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Problem Solving
Q10 — Proving a Cosec/Cot Identity
Prove that (cosecθ − cotθ)(cosecθ + cotθ) = 1.