Practice Maths

The Argand Diagram and Modulus

Key Terms

Argand diagram
The complex plane; z = a + bi is plotted as the point (a, b). Horizontal axis = real axis; vertical axis = imaginary axis.
Modulus |z|
The distance from the origin to the point (a, b); |z| = √(a² + b²).
Argument arg(z)
The angle θ from the positive real axis to z; principal value θ ∈ (−π, π].
Triangle inequality
|z + w| ≤ |z| + |w|.
Modulus properties
|zw| = |z||w|; |z/w| = |z|/|w|; |z̅| = |z|; |z|² = z · z̅.
Geometric addition
Complex number addition corresponds to vector addition in the Argand plane.

Argand Diagram and Modulus — Key Facts

Argand diagram: Plot z = a + bi as the point (a, b) in the complex plane. The horizontal axis is the real axis; the vertical axis is the imaginary axis.

Modulus: |z| = √(a² + b²)  —  the distance from the origin to the point (a, b)

Argument: arg(z) = θ where tan θ = b/a, chosen in the correct quadrant; θ ∈ (−π, π] (principal argument)

Key modulus properties:

|z · w| = |z| · |w|    |z/w| = |z|/|w|    |z̅| = |z|    |z|² = z · z̅

Triangle inequality: |z + w| ≤ |z| + |w|

Worked Example 1 — Plotting on the Argand Diagram

Plot and label: z⊂1; = 3 + 2i, z⊂2; = −1 + 3i, z⊂3; = −2 − i, z⊂4; = 4 − 3i

Re Im z₁ = 3+2i z₂ = −1+3i z₃ = −2−i z₄ = 4−3i

Worked Example 2 — Modulus and Argument

For z = −1 + √3 i, find |z| and arg(z).

|z| = √((−1)² + (√3)²) = √(1 + 3) = 2

z is in Quadrant 2 (Re < 0, Im > 0). Reference angle: tanα = √3/1, so α = π/3.

arg(z) = π − π/3 = 2π/3

Hot Tip: Always check which quadrant your complex number is in before computing the argument. tan−1(b/a) only gives the reference angle, not necessarily the correct argument. Draw a quick sketch!

The Complex Plane — Giving Geometry to Numbers

The Argand diagram (named after Jean-Robert Argand, 1806) is a coordinate plane where each complex number z = a + bi is plotted as the point (a, b). The horizontal axis represents real numbers; the vertical axis represents purely imaginary numbers. This geometric representation transforms algebraic operations into geometric transformations — a perspective that becomes essential in polar form and De Moivre’s theorem.

On the Argand diagram, the conjugate z̅ = a − bi is the reflection of z across the real axis. Adding two complex numbers corresponds to vector addition (parallelogram law). These geometric interpretations give deep insight into complex arithmetic.

Modulus as Distance

The modulus |z| = √(a² + b²) is simply the distance from the origin O to the point z, by Pythagoras’ theorem. This is why |z| ≥ 0 always, with |z| = 0 only when z = 0.

Key modulus properties (worth memorising):

  • |zw| = |z||w|: the modulus of a product equals the product of the moduli
  • |z/w| = |z|/|w|: the modulus of a quotient equals the quotient of the moduli
  • |z²| = |z|², and more generally |zn| = |z|n
  • |z̅| = |z|: the conjugate has the same distance from the origin
  • |z + w| ≤ |z| + |w| (triangle inequality): distance from O to z + w cannot exceed the sum of distances to z and w

Argument — The Angle

The argument arg(z) is the angle θ that the line from the origin to z makes with the positive real axis, measured anticlockwise. The principal argument is restricted to (−π, π], meaning −π < θ ≤ π.

To find arg(z) for z = a + bi:

  1. Compute the reference angle α = tan−1(|b|/|a|) (always positive, in first quadrant)
  2. Adjust based on the quadrant of (a, b):
    • Quadrant 1 (a > 0, b > 0): arg(z) = +α
    • Quadrant 2 (a < 0, b > 0): arg(z) = π − α
    • Quadrant 3 (a < 0, b < 0): arg(z) = −(π − α) = α − π
    • Quadrant 4 (a > 0, b < 0): arg(z) = −α

Special cases: arg(positive real) = 0, arg(negative real) = π, arg(positive imaginary) = π/2, arg(negative imaginary) = −π/2.

Geometric Sets in the Complex Plane

Conditions on |z| and arg(z) describe geometric regions. For example:

  • |z| = r is a circle of radius r centred at the origin
  • |z − z⊂0;| = r is a circle of radius r centred at z⊂0;
  • arg(z) = θ is a ray (half-line) from the origin at angle θ
  • |z − z⊂1;| = |z − z⊂2;| is the perpendicular bisector of the segment from z⊂1; to z⊂2;

These geometric interpretations are tested in exam problem-solving questions and are excellent for developing spatial reasoning.

Mastery Practice

  1. Fluency

    Q1 — Modulus Calculations

    Find |z| for: (a) z = 3 + 4i    (b) z = −5 + 12i    (c) z = 1 − i    (d) z = −6

  2. Fluency

    Q2 — Principal Argument

    Find arg(z) for: (a) z = 1 + i    (b) z = −√3 + i    (c) z = −1 − i    (d) z = 2i

  3. Fluency

    Q3 — Modulus Properties

    If |z| = 3 and |w| = 4, find: (a) |zw|    (b) |z/w|    (c) |z²|    (d) |z + w| can be at most how large?

  4. Fluency

    Q4 — Plotting on the Argand Diagram

    Describe the geometric relationship between z = 2 + 3i, z̅, −z, and −z̅ on the Argand diagram.

  5. Understanding

    Q5 — Modulus and Argument Together

    For z = −2 + 2i, find |z| and arg(z), then verify that z = |z|(cos(arg z) + i sin(arg z)).

  6. Understanding

    Q6 — Distance Between Two Complex Numbers

    Find the distance between z = 3 + i and w = −1 + 4i on the Argand diagram.

  7. Understanding

    Q7 — Geometric Locus

    Describe the set of all z satisfying: (a) |z| = 5    (b) |z − 2i| = 3

  8. Understanding

    Q8 — Argument of a Product

    If arg(z) = π/3 and arg(w) = π/4, find arg(zw). What property does this suggest about arguments?

  9. Problem Solving

    Q9 — Finding Complex Numbers from Geometric Conditions

    Find all complex numbers z such that |z| = 5 and Re(z) = 3.

  10. Problem Solving

    Q10 — Triangle Inequality Application

    If |z − 3| ≤ 1 and |w + i| ≤ 2, find the maximum possible value of |z + w|.