Practice Maths

Polynomial Equations with Complex Roots

Key Terms

Fundamental theorem of algebra
A polynomial of degree n has exactly n roots in ℂ (counting multiplicity).
Conjugate root theorem
If P(x) has real coefficients and z = a + bi is a root, then z̅ = a − bi is also a root.
Real quadratic factor
A pair of complex conjugate roots z and z̅ gives the real quadratic (x − z)(x − z̅) = x² − 2ax + (a²+b²).
Strategy for real polynomials
Given one complex root, write down its conjugate; build the quadratic factor; divide the polynomial.
Quadratic formula over ℂ
x = (−b ± √(b²−4ac)) / (2a); if discriminant < 0, roots are complex conjugates.
Vieta’s formulas
For ax² + bx + c = 0: sum of roots = −b/a; product of roots = c/a.

Polynomial Equations with Complex Roots — Key Facts

Fundamental Theorem of Algebra: Every polynomial of degree n with complex coefficients has exactly n roots in ℂ (counting multiplicity).

Conjugate Root Theorem: If a polynomial has real coefficients and z = a + bi (b ≠ 0) is a root, then z̅ = a − bi is also a root.

Building quadratic factors: If z = a + bi is a root, the corresponding real quadratic factor is (x − z)(x − z̅) = x² − 2ax + (a²+b²)

Strategy for cubics/quartics: If one complex root z is known, z̅ is also a root. Divide the polynomial by (x² − 2ax + (a²+b²)) to find remaining real factors.

Quadratic formula over ℂ: for ax²+bx+c=0, x = (−b ± √(b²−4ac))/(2a). If discriminant < 0, roots are complex conjugates.

Worked Example 1 — Solving a Quadratic with Complex Roots

Solve x² + 2x + 5 = 0 over ℂ.

Quadratic formula: x = (−2 ± √(4 − 20))/2 = (−2 ± √(−16))/2 = (−2 ± 4i)/2

Roots: x = −1 + 2i and x = −1 − 2i

These are conjugates of each other, as expected for a polynomial with real coefficients.

Worked Example 2 — Finding a Cubic with a Known Complex Root

A cubic polynomial P(x) with real coefficients has −1 as a root and 2 + i as a root. Find all roots and write P(x) in factored form (monic).

Step 1: By the conjugate root theorem, 2 − i is also a root.

Step 2: The quadratic factor from the complex pair is (x − (2+i))(x − (2−i)) = x² − 4x + 5.

Step 3: P(x) = (x + 1)(x² − 4x + 5)

All roots: x = −1, 2 + i, 2 − i

Hot Tip: The conjugate root theorem only applies when all coefficients are real. If the polynomial has complex coefficients, complex roots do not need to come in conjugate pairs.

The Fundamental Theorem of Algebra

One of the most celebrated results in all of mathematics is the Fundamental Theorem of Algebra: every polynomial of degree n (with complex, and in particular, real coefficients) has exactly n roots when counted with multiplicity in the complex number system ℂ. This theorem was first proved rigorously by Gauss in his 1799 doctoral thesis. It tells us that the complex numbers are “algebraically closed” — you can never escape ℂ by solving polynomial equations.

The Conjugate Root Theorem

For polynomials with real coefficients, complex roots always come in conjugate pairs. If z = a + bi (with b ≠ 0) is a root, then so is z̅ = a − bi. The proof is elegant: if P(z) = 0 and all coefficients are real, then taking the conjugate of both sides gives P(z̅) = 0̅ = 0 (since conjugation distributes over addition and multiplication, and conjugating a real number leaves it unchanged).

This theorem is enormously practical: once you find one complex root of a real polynomial, you immediately know another root — its conjugate. For a cubic with real coefficients, there must be either three real roots, or one real root and one conjugate pair.

Building Real Quadratic Factors

Given a complex conjugate pair z = a + bi and z̅ = a − bi, the corresponding quadratic factor is:

(x − z)(x − z̅) = x² − (z + z̅)x + z z̅ = x² − 2ax + (a² + b²)

This quadratic has real coefficients and is irreducible over ℝ (it cannot be factored into real linear factors). Memorising the structure x² − 2ax + (a²+b²) saves time — the middle coefficient is minus twice the real part, and the constant term is the squared modulus.

Strategy for Higher-Degree Polynomials

To factor a cubic or quartic with real coefficients when one complex root is known:

Step 1: Write down the conjugate root as well (conjugate root theorem).

Step 2: Form the real quadratic factor (x² − 2ax + (a²+b²)).

Step 3: Divide the polynomial by this quadratic factor using polynomial long division. The quotient will have real coefficients.

Step 4: Solve the quotient equation to find remaining roots.

Solving zn = c Over the Complex Numbers

Equations of the form zn = c (where c is a real or complex number) are solved using polar form. Write c = r cisθ, then z = r1/n cis((θ + 2kπ)/n) for k = 0, 1, …, n−1. This gives n equally spaced roots on a circle of radius r1/n. When c is a positive real number, the roots include one real root (k=0) and the rest are complex, coming in conjugate pairs.

Connecting to the Fundamental Theorem

Once we know all n roots z&sub1;, z&sub2;, …, zn of a degree-n polynomial P(x), we can write P(x) = a(x − z&sub1;)(x − z&sub2;) … (x − zn) where a is the leading coefficient. For polynomials with real coefficients, complex roots pair up, and we group each pair into a real quadratic factor to express P(x) as a product of real linear and real quadratic factors. This factored form over ℝ is important for integration, partial fractions, and graphical analysis.

Mastery Practice

  1. Fluency

    Q1 — Solving Quadratics with Complex Roots

    Solve each equation over ℂ:

    (a) x² + 4 = 0    (b) x² + 6x + 13 = 0    (c) x² − 4x + 8 = 0

  2. Fluency

    Q2 — Applying the Conjugate Root Theorem

    A polynomial with real coefficients has the given root. Write down another root that must also exist:

    (a) 3 + 4i    (b) −1 + √2 i    (c) 5i    (d) −3 − 7i

  3. Fluency

    Q3 — Building a Quadratic from a Complex Root

    Find the monic quadratic with real coefficients that has the given root:

    (a) 1 + 3i    (b) −2 + i    (c) 4i

  4. Fluency

    Q4 — Factoring z4 − 1

    Find all roots of z4 − 1 = 0 over ℂ.

  5. Understanding

    Q5 — Cubic with One Complex Root Known

    A cubic polynomial P(x) with real coefficients has roots including 1 − 2i. Given P(x) is monic and has −3 as its third root, write P(x) in fully factored form and expand it.

  6. Understanding

    Q6 — Solving a Quartic Using Factor Theorem

    Given that 2 + i is a root of P(x) = x4 − 4x³ + 6x² − 4x − 5, find all roots.

  7. Understanding

    Q7 — Finding a Polynomial from Its Roots

    Find a monic cubic polynomial with real coefficients, given that two of its roots are x = 2 and x = 1 + 3i.

  8. Understanding

    Q8 — Sum and Product of Complex Roots

    A quadratic with real coefficients has roots α and β. Given that α + β = 4 and αβ = 13, find α and β, and write the quadratic.

  9. Problem Solving

    Q9 — Solving a Cubic Completely

    Given that 2i is a root of P(x) = x³ − 3x² + 4x − 12, find all roots and express P(x) as a product of linear and irreducible quadratic factors over ℝ.

  10. Problem Solving

    Q10 — Quartic with Two Complex Conjugate Pairs

    Find a monic degree-4 polynomial with real coefficients whose roots are 1 + i and 3i.