Complex Numbers in Cartesian Form
Key Terms
- Complex number z
- A number z = a + bi where a, b ∈ ℝ and i² = −1.
- Real part Re(z)
- The coefficient a in z = a + bi.
- Imaginary part Im(z)
- The coefficient b (NOT bi) in z = a + bi; a common error is to include the i.
- Complex conjugate z̅
- z̅ = a − bi; z · z̅ = a² + b² (always a non-negative real number).
- Equal complex numbers
- a + bi = c + di if and only if a = c AND b = d simultaneously (equate real and imaginary parts).
- Powers of i
- i¹ = i, i² = −1, i³ = −i, i&sup4; = 1; the cycle repeats with period 4.
Complex Numbers — Key Facts
Imaginary unit: i is defined by i² = −1, so i = √(−1)
Cartesian form: z = a + bi, where a = Re(z) is the real part, b = Im(z) is the imaginary part
Conjugate: If z = a + bi then z̅ = a − bi
Key product: z · z̅ = a² + b² (always a non-negative real number)
Equal complex numbers: a + bi = c + di if and only if a = c AND b = d
Powers of i: i¹ = i, i² = −1, i³ = −i, i&sup4; = 1, then the cycle repeats
Worked Example 1 — Identifying Parts and Conjugates
For each complex number, state the real part, imaginary part, and conjugate:
(a) z = 3 + 5i (b) z = −2 − 7i (c) z = 4 (a real number) (d) z = −3i (a pure imaginary)
(a) Re(z) = 3, Im(z) = 5, z̅ = 3 − 5i
(b) Re(z) = −2, Im(z) = −7, z̅ = −2 + 7i
(c) Re(z) = 4, Im(z) = 0, z̅ = 4 (real numbers are their own conjugates)
(d) Re(z) = 0, Im(z) = −3, z̅ = 3i
Worked Example 2 — Simplifying Powers of i and Computing z·z̅
Simplify: (a) i³ (b) i10 (c) z · z̅ for z = 3 + 4i
(a) i³ = i² × i = −1 × i = −i
(b) i10 = (i&sup4;)² × i² = 1² × (−1) = −1
(c) z · z̅ = (3 + 4i)(3 − 4i) = 3² + 4² = 9 + 16 = 25
Why Do We Need Complex Numbers?
The real number system has a fundamental gap: you cannot take the square root of a negative number. Consider the equation x² + 1 = 0. Rearranging gives x² = −1, but no real number satisfies this — squaring any real number always gives a non-negative result. For centuries, mathematicians dismissed such equations as “impossible.”
The solution was to define a new symbol i such that i² = −1. This is not a trick or a sleight of hand — it is a legitimate extension of the number system, just as fractions extended whole numbers and irrationals extended rationals. The resulting system of complex numbers is complete in a profound sense: every polynomial equation has a solution in ℂ (the Fundamental Theorem of Algebra).
The Cartesian Form a + bi
Every complex number can be written as z = a + bi where a and b are real numbers. We call this Cartesian form (or rectangular form). The number a is the real part Re(z), and b is the imaginary part Im(z) — note that Im(z) is the real number b, not the expression bi.
Special cases: when b = 0, z = a is a real number; when a = 0, z = bi is a pure imaginary number. This shows that the real numbers are a subset of the complex numbers.
The Imaginary Unit and Powers of i
Since i² = −1, we can simplify any power of i by reducing the exponent modulo 4:
| Power | Value | Reasoning |
|---|---|---|
| i¹ | i | definition |
| i² | −1 | definition |
| i³ | −i | i² × i = −1 × i |
| i&sup4; | 1 | i² × i² = (−1)(−1) |
| i&sup5; | i | i&sup4; × i = 1 × i |
To simplify in: divide n by 4 and check the remainder. Remainder 0 → 1, remainder 1 → i, remainder 2 → −1, remainder 3 → −i.
The Conjugate and its Key Property
The conjugate of z = a + bi is z̅ = a − bi. Geometrically, taking the conjugate reflects the number across the real axis on the Argand diagram (covered in a later lesson).
The most important algebraic property is: z · z̅ = (a + bi)(a − bi) = a² + b². This is a real number, and it is always ≥ 0. This property is the engine behind dividing complex numbers — multiplying numerator and denominator by the conjugate of the denominator converts the denominator to a real number.
Equality of Complex Numbers
Two complex numbers are equal if and only if their real parts are equal AND their imaginary parts are equal. This gives us a powerful technique: if we know a + bi = c + di, we can equate real parts (a = c) and imaginary parts (b = d) to solve for unknowns. This technique appears constantly throughout Unit 2.
Common error: Students sometimes write i² = +1 instead of −1. Always remember: i² = −1 by definition.
Mastery Practice
-
Fluency
Q1 — Real and Imaginary Parts
For each complex number, state Re(z), Im(z), and z̅:
(a) z = 5 + 2i (b) z = −3 + 4i (c) z = 7i (d) z = −6
-
Fluency
Q2 — Powers of i
Simplify: (a) i6 (b) i11 (c) i20 (d) i35
-
Fluency
Q3 — Computing z · z̅
Calculate z · z̅ for: (a) z = 2 + 3i (b) z = 5 − i (c) z = −1 + 2i
-
Fluency
Q4 — Simplifying Square Roots of Negatives
Write in terms of i: (a) √(−9) (b) √(−25) (c) √(−7)
-
Understanding
Q5 — Equating Real and Imaginary Parts
Find real numbers x and y if: (a) x + yi = 5 − 3i (b) (2x + 1) + (y − 3)i = 7 + 2i
-
Understanding
Q6 — Solve Using i
Solve each equation over ℂ: (a) x² + 9 = 0 (b) x² + 2x + 5 = 0
-
Understanding
Q7 — Conjugate Properties
Given z = 3 − 4i, verify that: (a) Re(z) + Re(z̅) = 2 Re(z) (b) z + z̅ is real (c) z − z̅ is purely imaginary
-
Understanding
Q8 — Finding Unknown Complex Numbers
Find z = a + bi given that z + 2z̅ = 9 − 6i.
-
Problem Solving
Q9 — Simplifying a Complex Expression
Simplify (1 + i)² + (1 − i)² and hence explain the relationship between (1 + i) and (1 − i).
-
Problem Solving
Q10 — Proof Using Conjugates
Prove that for any complex number z, z² + (z̅)² is always a real number.