Topic Review — Further Differentiation
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Fluency
Q1 — Chain rule: identify and differentiate
Differentiate each function using the chain rule.
(a) y = (3x + 1)5 (b) y = (x² − 4)3 (c) y = √(2x + 7) (d) y = 1/(x + 3)²
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Fluency
Q2 — Product rule: basic applications
Differentiate each function using the product rule.
(a) y = x(x + 5) (b) y = x²(2x − 3) (c) y = (x + 1)(x² + 4) (d) y = x³√x
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Fluency
Q3 — Quotient rule: basic applications
Differentiate each function using the quotient rule.
(a) y = (x + 3)/(x − 1) (b) y = x²/(x + 2) (c) y = (2x + 1)/x² (d) y = 1/(x² + 4)
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Understanding
Q4 — Chain rule: gradient at a point
For each curve, find the gradient at the specified point.
(a) y = (2x − 1)&sup4; at x = 1 (b) y = (x² + 2)³ at x = 1 (c) y = √(3x + 1) at x = 1 (d) y = (1 − 2x)³ at x = 0
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Understanding
Q5 — Product rule: equation of tangent
Find the equation of the tangent to each curve at the given point.
(a) y = x(x + 4) at x = 2 (b) y = x²(x − 1) at x = 2 (c) y = (x + 1)(x² − 2) at x = 1
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Understanding
Q6 — Quotient rule: turning points
Find all x-values where dy/dx = 0 for each function.
(a) y = x/(x² + 3) (b) y = x²/(x + 2) (c) y = (x − 2)/(x² + 1)
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Understanding
Q7 — Choosing the correct rule
State which rule (chain, product, quotient, or power rule alone) you would use first, and then differentiate each function.
(a) y = (5x − 2)³ (b) y = x(x + 1)4 (c) y = (x + 1)/(x² + x) (d) y = 3x4 − 7x² + 2
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Problem Solving
Q8 — Chain rule: stationary points and nature
For the curve y = (x² − 4)4:
(a) Find dy/dx. (b) Find all stationary points. (c) Classify each stationary point using a sign diagram. (d) Find the coordinates of each.
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Problem Solving
Q9 — Product rule combined with chain rule
Find dy/dx for each function. Factorise your answers fully.
(a) y = x²(x + 1)5 (b) y = (x − 1)(2x + 3)&sup4; (c) y = x(x² − 1)³
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Problem Solving
Q10 — Quotient rule: nature of stationary points
For y = (x² + 1)/(x):
(a) Find dy/dx using the quotient rule. (b) Find all stationary points. (c) Determine the nature of each. (d) Verify by rewriting y = x + 1/x and differentiating using the power rule.
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Problem Solving
Q11 — Motion: chain rule application
A particle moves along a line. Its displacement at time t ≥ 0 is s(t) = (t² + 1)³ metres.
(a) Find the velocity v = ds/dt. (b) Find the acceleration a = dv/dt. (c) Find the velocity when t = 1. (d) Is the particle ever stationary (v = 0)? Justify.
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Problem Solving
Q12 — Applied optimisation using quotient rule
A function modelling efficiency is E(x) = x/(x² + 1) for x ≥ 0.
(a) Find E′(x). (b) Find the value of x that maximises E(x). (c) Find the maximum value of E. (d) Confirm it is a maximum using a sign diagram or second derivative argument.
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Problem Solving
Q13 — Full mixed: identify rule, differentiate, apply
For each function, state the rule(s) required and find dy/dx. Then find the gradient at x = 1.
(a) y = x²(3x − 1)³ (b) y = (x + 1)² / (x² + 1) (c) y = (x² − 1)(x² + 1)4
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Problem Solving
Q14 — Rate of change application
A population of bacteria at time t hours is modelled by P(t) = 100t / (t² + 9) (hundreds of bacteria).
(a) Find P′(t). (b) Find the time at which the population peaks. (c) What is the maximum population? (d) Find the rate of change of population at t = 6. Is the population increasing or decreasing?
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Problem Solving
Q15 — Extended: all three rules
Consider the function f(x) = x(x + 1)² / (x² + 1).
(a) Find the numerator's derivative using the product and chain rule. (b) Apply the quotient rule to find f′(x). (c) Evaluate f′(0). (d) Determine whether f has a stationary point at x = 0.