Practice Maths

L09 — Introduction to Polynomials

Key Terms

  • Polynomial — a sum of terms of the form axn where n is a non-negative integer and a is a real number
  • Degree — the highest power of x with a non-zero coefficient
  • Leading coefficient — the coefficient of the highest-degree term
  • Standard form — terms written in descending order of degree: anxn + an−1xn−1 + … + a0
  • Evaluate P(a) — substitute x = a into the polynomial and calculate the result
  • End behaviour — how the graph of P(x) behaves as x → +∞ or x → −∞

What is a Polynomial?

A polynomial in x is an expression of the form:

anxn + an−1xn−1 + … + a1x + a0

where n is a non-negative integer and the coefficients an, …, a0 are real numbers with an ≠ 0.

Degree and Classification

NameDegreeGeneral FormExample
Constant0a7
Linear1ax + b3x − 2
Quadratic2ax² + bx + cx² + 5x − 3
Cubic3ax³ + bx² + cx + d2x³ − x + 4
Quartic4ax4 + …x4 − 3x² + 1
  • The degree is the highest power of x with a non-zero coefficient.
  • The leading coefficient is the coefficient of the highest-degree term.
  • Standard form means terms are written in descending order of degree.
x y -2 -1 1 2 -3 -2 -1 1 2 3 local max local min y = x³ − 4x x→-∞: y→-∞ x→+∞: y→+∞
A cubic polynomial y = x³ − 4x showing x-intercepts, local max/min, and end behaviour

End Behaviour

DegreeLeading CoeffAs x → −∞As x → +∞
OddPositive (+)y → −∞y → +∞
OddNegative (−)y → +∞y → −∞
EvenPositive (+)y → +∞y → +∞
EvenNegative (−)y → −∞y → −∞

The end behaviour is determined entirely by the degree and sign of the leading coefficient.

Hot Tip: Not every algebraic expression is a polynomial! √x = x½, 1/x = x−1, and x0.5 all have non-integer or negative exponents — so they are not polynomials. A polynomial's powers of x must always be non-negative integers: 0, 1, 2, 3, …

Evaluating a Polynomial

Example: P(x) = x³ − 2x + 3. Find P(−2).
P(−2) = (−2)³ − 2(−2) + 3 = −8 + 4 + 3 = −1

What Makes Something a Polynomial?

A polynomial is a sum of terms of the form axn where n must be a non-negative integer (0, 1, 2, 3, …). The key restrictions are:

  • No negative powers of x (so 1/x = x−1 is not allowed)
  • No fractional powers of x (so √x = x½ is not allowed)
  • Coefficients can be any real number (including fractions and negative numbers)
Worked Example 1: Is it a polynomial?

Classify each expression as a polynomial or not a polynomial. If it is a polynomial, state its degree and leading coefficient.
(a) 3x&sup4; − x² + 7     (b) x² + √x + 1     (c) −5x³ + 2x − 4     (d) 2/x + x

Solution:
(a) Polynomial. Degree 4, leading coefficient 3.
(b) Not a polynomial — √x = x½ has a fractional exponent.
(c) Polynomial. Degree 3, leading coefficient −5.
(d) Not a polynomial — 2/x = 2x−1 has a negative exponent.

Standard Form and Evaluating Polynomials

Standard form lists terms in descending order of degree. For example, 3 + 2x − x² in standard form is −x² + 2x + 3.

To evaluate P(a), substitute every x with the value a and calculate carefully. Use brackets around negative values.

Worked Example 2: Evaluate a polynomial

For P(x) = 2x³ − x + 4, find P(0), P(2), and P(−1).

Solution:
P(0) = 2(0)³ − (0) + 4 = 0 − 0 + 4 = 4
P(2) = 2(2)³ − (2) + 4 = 16 − 2 + 4 = 18
P(−1) = 2(−1)³ − (−1) + 4 = −2 + 1 + 4 = 3

Polynomial Arithmetic

To add or subtract polynomials, collect like terms (terms with the same degree). To multiply, use the distributive law and remember that xm × xn = xm+n.

Worked Example 3: Add and subtract polynomials

(a) (4x³ − 2x + 1) + (x³ + 3x² + x − 5)
(b) (3x² + 5x − 2) − (x² − 2x + 4)

Solution:
(a) Collect like terms: (4+1)x³ + 3x² + (−2+1)x + (1−5) = 5x³ + 3x² − x − 4
(b) Distribute the minus: (3−1)x² + (5+2)x + (−2−4) = 2x² + 7x − 6

End Behaviour

For large values of |x|, a polynomial is dominated by its highest-degree term. So the end behaviour depends only on the degree and the sign of the leading coefficient:

  • Odd degree, positive leading coeff: falls left (→ −∞), rises right (→ +∞)
  • Odd degree, negative leading coeff: rises left, falls right
  • Even degree, positive leading coeff: rises at both ends (→ +∞ both sides)
  • Even degree, negative leading coeff: falls at both ends (→ −∞ both sides)
Worked Example 4: Describe end behaviour

State the end behaviour of y = −3x4 + 5x² − x + 1.

Solution:
Degree = 4 (even). Leading coefficient = −3 (negative).
⇒ As x → −∞, y → −∞  and  as x → +∞, y → −∞.
The graph falls on both ends (like an upside-down U overall).
  1. Degree and leading coefficient. Fluency

    For each polynomial, state the degree and the leading coefficient.

    • (a) 3x² − 2x + 5
    • (b) x5 − 4x³ + 2
    • (c) −2x³ + x − 7
    • (d) 6x4 − 3x² + x
  2. Standard form. Fluency

    Rewrite each polynomial in standard form (descending powers of x). State the degree.

    • (a) 3 + 2x − x²
    • (b) 4x³ − 2 + x − 5x²
    • (c) x + 3x4 − x²
    • (d) 5 − 3x + 7x² − x³
  3. Evaluate the polynomial. Fluency

    For P(x) = 2x³ − 3x² + x − 4, evaluate:

    • (a) P(0)
    • (b) P(1)
    • (c) P(−1)
    • (d) P(2)
  4. Add and subtract polynomials. Fluency

    Expand the brackets and collect like terms.

    • (a) (3x² − 2x + 1) + (x² + 4x − 3)
    • (b) (5x³ − 2x + 4) − (2x³ + x² − 3x + 1)
    • (c) (2x4 − x² + 3x) + (x³ + 4x² − x − 5)
    • (d) (x³ − 4x² + 2x − 1) − (x³ + 2x − 5)
  5. Multiply polynomials. Understanding

    Expand and simplify.

    • (a) x(x² − 3x + 2)
    • (b) (x + 2)(x² − x + 3)
    • (c) (x − 1)(x + 1)(x − 2)
    • (d) (2x + 1)(x² − 2x + 3)
  6. End behaviour. Understanding

    For each polynomial, use the degree and leading coefficient to describe the end behaviour as x → −∞ and as x → +∞.

    • (a) y = x³ − 2x + 1
    • (b) y = −x4 + 3x²
    • (c) y = 2x5 − x³
    • (d) y = −3x² + 5x − 1
  7. Polynomial from factored form. Understanding

    For P(x) = (x − 1)(x + 2)(x − 3):

    • (a) State the x-intercepts of the graph.
    • (b) Expand to standard form.
    • (c) Find the y-intercept (the value of P(0)).
    • (d) Describe the end behaviour.
  8. Does the point lie on the polynomial? Understanding

    P(x) = x³ − 2x² − x + 2. Determine whether each point lies on the graph of P.

    • (a) (0, 2)
    • (b) (1, 0)
    • (c) (2, 1)
    • (d) (−1, 0)
  9. Find the unknown coefficient. Problem Solving

    P(x) = kx³ − 3x² + 2x − 1. Given that P(2) = 5, find the value of k.

  10. Construct a polynomial from zeros. Problem Solving

    A cubic polynomial has the form P(x) = k(x − a)(x − b)(x − c). It has x-intercepts at x = −2, x = 0, and x = 3, and passes through the point (1, 12).

    • (a) Write the unscaled factored form P(x) = k ⋅ x(x + 2)(x − 3).
    • (b) Use the point (1, 12) to find k.
    • (c) Write the full equation of P(x) in standard form.